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Title: string replace question
Post by: mueer01 on January 26, 2016, 05:58:14 AM

Hello,

I want to replace the string
xxx"100%"xxx
by
xxx"25%"xxx

I tried

if buf == "xxx"100%"xxx" THEN buf = "xxx"25%"xxx"
if buf == ""xxx"100%%"xxx"" THEN buf = ""xxx"25%%"xxx""
if buf == """xxx"100%%"xxx""" THEN buf = """xxx"25%%"xxx"""
if buf == """"xxx"100%%"xxx"""" THEN buf = """"xxx"25%%"xxx""""

all is wrong! Any idea?

Regards,
Erhard

Title: Re: string replace question
Post by: td on January 26, 2016, 06:36:23 AM

You are close but

Code (winbatch) Select

buf = "xxx""100%%""xxx"
if buf == "xxx""100%%""xxx"       THEN buf = "xxx""25%%""xxx"

is likely what you want. You can also do something like this:

Code (winbatch) Select

buf = 'xxx"100%%"xxx'
if buf == 'xxx"100%%"xxx'       THEN buf = 'xxx"25%%"xxx'

which many may find more readable.

You can also use the StrReplace function, if you can make a few assumptions about your strings:

Code (winbatch) Select

buf = 'xxx"100%%"xxx'
buf=StrReplace(buf,"100%%", "25%%")

Title: Re: string replace question
Post by: mueer01 on January 26, 2016, 06:50:45 AM

YEPP! That works!
Many thanks, 99 pts for you.

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All Things WinBatch => WinBatch => Topic started by: mueer01 on January 26, 2016, 05:58:14 AM