string replace question

[mueer01]

Hello,

I want to replace the string
xxx"100%"xxx
by
xxx"25%"xxx

I tried

if buf == "xxx"100%"xxx"             THEN buf = "xxx"25%"xxx"   
if buf == ""xxx"100%%"xxx""       THEN buf = ""xxx"25%%"xxx""   
if buf == """xxx"100%%"xxx"""    THEN buf = """xxx"25%%"xxx"""   
if buf == """"xxx"100%%"xxx"""" THEN buf = """"xxx"25%%"xxx""""   

all is wrong! Any idea?

Regards,
Erhard

[td]

You are close but

Code (winbatch) Select Expand

buf = "xxx""100%%""xxx"
if buf == "xxx""100%%""xxx"       THEN buf = "xxx""25%%""xxx" 

is likely what you want.  You can also do something like this:

Code (winbatch) Select Expand

buf = 'xxx"100%%"xxx'
if buf == 'xxx"100%%"xxx'       THEN buf = 'xxx"25%%"xxx' 

which many may find more readable.

You can also use the StrReplace function, if you can make a few assumptions about your strings:

Code (winbatch) Select Expand

buf = 'xxx"100%%"xxx'
buf=StrReplace(buf,"100%%", "25%%")


[mueer01]

YEPP! That works!
Many thanks, 99 pts for you.

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