Running from studio single process in debug mode

[erezpaz]

Hi,

I am using an example from here how to run only one process instate of my program.
DupThread = 0
kernel32=strcat(dirwindows(1),"kernel32.dll")
ERROR_ALREADY_EXISTS=183
mutexname="*mywinbatchappnamev1.x*"
hmutex=dllcall(kernel32,long:"CreateMutexA",lpnull,long:0,lpstr:mutexname)
if DllLastError()==ERROR_ALREADY_EXISTS ;mutex exist an hinstance is running
display(5,NameVer,"Only 1 instance of %tool% is allowed.")
exit
end if
It works fine when i run the exe directly. If i run it from the studio in regular mode or debug mode i get the message and the program exit.
Can you help me understand how to prevent that?

Thanks

[kdmoyers]

Just a data point: it's working fine for me on my Win7 and Win10 machines.
(I had to define NameVer)
Thanks for the cool example!
$0.02
-Kirby

[td]

When you call your function from the WinBatch Studio debugger,  the mutex remains in existence even after the debugging session ends because the WinBatch Studio process is still running.

Also, is there some reason why you are not using the AppExist function instead of fiddling with a DllCall?

[td]

If there is a good reason to be using a DllCall instead of AppExist, you can always simply close the mutex handle using the Win32 CloseHandle function just before the script terminates.